5y^2+19y=30

Solution for 5y^2+19y=30 equation:

5y^2+19y=30

We move all terms to the left:

5y^2+19y-(30)=0

a = 5; b = 19; c = -30;
Δ = b2-4ac
Δ = 192-4·5·(-30)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-31}{2*5}=\frac{-50}{10}
=-5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+31}{2*5}=\frac{12}{10}
=1+1/5
$